Jag kände inte till find_in_set()-funktionen och tog ett mer handgjordt tillvägagångssätt. Inte för att det är vettigt med tanke på det första svaret, men jag lägger upp det ändå:
SELECT id
FROM (
SELECT '757392' AS id UNION
SELECT '733602' UNION
SELECT '749955' UNION
SELECT '744304' UNION
SELECT '746852' UNION
SELECT '753904' UNION
SELECT '755117' UNION
SELECT '636163' UNION
SELECT '564931' UNION
SELECT '740787' UNION
SELECT '751450' UNION
SELECT '743799' UNION
SELECT '643918' UNION
SELECT '749903' UNION
SELECT '571888' UNION
SELECT '30207' UNION
SELECT '705953' UNION
SELECT '749120' UNION
SELECT '749001' UNION
SELECT '749192' UNION
SELECT '749978' UNION
SELECT '750840' UNION
SELECT '544228' UNION
SELECT '702121' UNION
SELECT '746246' UNION
SELECT '383667' UNION
SELECT '558790' UNION
SELECT '585628' UNION
SELECT '592771' UNION
SELECT '745818' UNION
SELECT '749375' UNION
SELECT '241209' UNION
SELECT '749235' UNION
SELECT '746860' UNION
SELECT '748318' UNION
SELECT '748016' UNION
SELECT '748951' UNION
SELECT '747321' UNION
SELECT '748684' UNION
SELECT '748225' UNION
SELECT '565375' UNION
SELECT '748673' UNION
SELECT '747869' UNION
SELECT '748522' UNION
SELECT '748335' UNION
SELECT '744775' UNION
SELECT '672229' UNION
SELECT '578056' UNION
SELECT '713127' UNION
SELECT '740234' UNION
SELECT '632608' UNION
SELECT '711135' UNION
SELECT '746528' UNION
SELECT '362131' UNION
SELECT '742223' UNION
SELECT '746567' UNION
SELECT '745224' UNION
SELECT '332989' UNION
SELECT '439837' UNION
SELECT '745418' UNION
SELECT '673582' UNION
SELECT '269584' UNION
SELECT '742606' UNION
SELECT '745135' UNION
SELECT '746950' UNION
SELECT '476134' UNION
SELECT '740830' UNION
SELECT '742949' UNION
SELECT '276934') AS id_list
WHERE id NOT IN (
SELECT id
FROM users);