Försök:
SELECT p.id as pack_id,
XMLELEMENT(name taskgroup,
XMLATTRIBUTES(tg.id as id),
XMLAGG(XMLELEMENT(name task,
XMLATTRIBUTES(t.id as id)) as xml_task_group
FROM packages p
JOIN package_taskgroup pt ON p.id = pt.package_id
JOIN taskgroups tg on pt.taskgroup_id = tg.id
JOIN taskgroup_task tt on tg.id = tt.taskgroup_id
JOIN tasks t on tt.task_id = t.id
WHERE p.id = somePackageId
GROUP BY p.id, tg.id
Detta ger dig alla uppgiftsgrupper för p.id
du angav.
Sedan:
SELECT XMLELEMENT(name package,
XMLATTRIBUTES(pack_id as id),
XMLAGG(xml_task_group))
FROM (previous SELECT here)
Detta ger dig den struktur du angav.
Detaljer:XMLAGG , XML-funktioner
Joined select kommer att se ut så här:
SELECT XMLELEMENT(name package,
XMLATTRIBUTES(pack_id as id),
XMLAGG(xml_task_group))
FROM (SELECT p.id as pack_id,
XMLELEMENT(name taskgroup,
XMLATTRIBUTES(tg.id as id),
XMLAGG(XMLELEMENT(name task,
XMLATTRIBUTES(t.id as id)
))) as xml_task_group
FROM packages p
JOIN package_taskgroup pt ON p.id = pt.package_id
JOIN taskgroups tg on pt.taskgroup_id = tg.id
JOIN taskgroup_task tt on tg.id = tt.taskgroup_id
JOIN tasks t on tt.task_id = t.id
WHERE p.id = somePackageId
GROUP BY p.id, tg.id) t
GROUP BY pack_id
Jag kopierade helt enkelt det första valet till FROM
klausul i den andra.