Du kan använda nedanstående fråga-
SELECT a.PK , a.Name, a.Email,
SUBSTRING_INDEX(GROUP_CONCAT(i.Image_Name),',',1) AS Image_name_1,
IF((LENGTH(GROUP_CONCAT(i.Image_Name)) - LENGTH(GROUP_CONCAT(i.Image_Name SEPARATOR ''))) < 1,'',SUBSTRING_INDEX(SUBSTRING_INDEX(GROUP_CONCAT(i.Image_Name),',',2),',',-1)) AS Image_name_2,
IF((LENGTH(GROUP_CONCAT(i.Image_Name)) - LENGTH(GROUP_CONCAT(i.Image_Name SEPARATOR ''))) < 2,'',SUBSTRING_INDEX(SUBSTRING_INDEX(SUBSTRING_INDEX(GROUP_CONCAT(i.Image_Name),',',3),',',-1),',',-1)) AS Image_name_3,
IF((LENGTH(GROUP_CONCAT(i.Image_Name)) - LENGTH(GROUP_CONCAT(i.Image_Name SEPARATOR ''))) < 3,'',SUBSTRING_INDEX(GROUP_CONCAT(i.Image_Name),',',-1)) AS Image_name_4
FROM `advertiser` a
LEFT JOIN category c ON a.PK = c. FK
LEFT JOIN images I ON a.PK = i.FK
WHERE c.FK = 1
GROUP BY a.PK, a.Name,a.Email;