Oracle Pivot-fråga ger kolumner med citattecken runt kolumnnamnen. Vad?

du kan tillhandahålla alias till de nya kolumnerna i pivot uttalandets IN sats.(OBS:Detta skiljer sig från standarden där sats IN() som inte tillåter alias.)

with testdata as
(
    select 'Fred' First_Name, 10 Items from dual
    union
    select 'John' First_Name, 5  Items from dual
    union 
    select 'Jane' First_Name, 12 Items from dual
    union
    select 'Fred' First_Name, 15 Items from dual
)
select * from testdata
pivot (
      sum(Items) 
      for First_Name
      in ('Fred' as fred,'John' as john,'Jane' as jane)
      )

och även för din aggregerade klausul som är nödvändig om du har flera klausuler...

with testdata as
(
    select 'Fred' First_Name, 10 Items from dual
    union
    select 'John' First_Name, 5  Items from dual
    union 
    select 'Jane' First_Name, 12 Items from dual
    union
    select 'Fred' First_Name, 15 Items from dual
)
select * from testdata
pivot (
    sum(Items) itmsum,
    count(Items) itmcnt
    for First_Name
    in ('Fred' as fred,'John' as john,'Jane' as jane)
   )

returnerar

FRED_ITMSUM FRED_ITMCNT JOHN_ITMSUM JOHN_ITMCNT JANE_ITMSUM JANE_ITMCNT
----------- ----------- ----------- ----------- ----------- -----------
         25           2           5           1          12           1

Naturligtvis kan du sedan gå full cirkel och använda standard oracle aliasing och byta namn på dem till vad du vill, inklusive att sätta tillbaka citattecken igen.

with testdata as
(
    select 'Fred' First_Name, 10 Items from dual
    union
    select 'John' First_Name, 5  Items from dual
    union 
    select 'Jane' First_Name, 12 Items from dual
    union
    select 'Fred' First_Name, 15 Items from dual
)
select FRED_ITMSUM "Fred's Sum", FRED_ITMCNT "Fred's Count"
     , JOHN_ITMSUM "John's Sum", JOHN_ITMCNT "John's Count"
     , JANE_ITMSUM "Janes's Sum", JANE_ITMCNT "Janes's Count"
from testdata
pivot (
    sum(Items) itmsum,
    count(Items) itmcnt
    for First_Name
    in ('Fred' as fred,'John' as john,'Jane' as jane)
   )

ger

Fred's Sum Fred's Count John's Sum John's Count Janes's Sum Janes's Count
---------- ------------ ---------- ------------ ----------- -------------
        25            2          5            1          12             1