Generera CREATE-skript för en lista med index

Du är ganska nära, skulle jag säga - jag provade det här, kan du verifiera om det här fungerar för dig och visar dig de förväntade 122 indexen som ska återskapas?

UPPDATERA :tillagd funktionalitet för att bestämma CLUSTERED vs. ICLUSTERED indextyp och för att lägga till INKLUDERADE kolumner till indexdefinitionen.

WITH indexCTE AS
(
    SELECT DISTINCT 
        i.index_id, i.name, i.object_id
    FROM 
        sys.indexes i 
    INNER JOIN
        sys.index_columns ic 
           ON i.index_id = ic.index_id AND i.object_id = ic.object_id
    WHERE 
        EXISTS (SELECT * FROM sys.columns c 
                 WHERE c.collation_name = 'Modern_Spanish_CI_AS' 
                 AND c.column_id = ic.column_id AND c.object_id = ic.object_id)
), 
indexCTE2 AS
(
    SELECT 
        indexCTE.name 'IndexName', 
        OBJECT_NAME(indexCTE.object_ID) 'TableName',
        CASE indexCTE.index_id 
          WHEN 1 THEN 'CLUSTERED'
          ELSE 'NONCLUSTERED'
        END AS 'IndexType', 
        (SELECT DISTINCT c.name + ','
         FROM 
            sys.columns c 
         INNER JOIN
            sys.index_columns ic 
               ON c.object_id = ic.object_id AND ic.column_id = c.column_id AND ic.Is_Included_Column = 0
         WHERE
            indexCTE.OBJECT_ID = ic.object_id 
            AND indexCTE.index_id = ic.index_id 
         FOR XML PATH('')
        ) ixcols,
        ISNULL(
        (SELECT DISTINCT c.name + ','
         FROM 
            sys.columns c 
         INNER JOIN
            sys.index_columns ic 
               ON c.object_id = ic.object_id AND ic.column_id = c.column_id AND ic.Is_Included_Column = 1
         WHERE
            indexCTE.OBJECT_ID = ic.object_id 
            AND indexCTE.index_id = ic.index_id 
         FOR XML PATH('')
        ), '') includedcols
    FROM 
        indexCTE
) 
SELECT 
    'CREATE ' + IndexType + ' INDEX ' + IndexName + ' ON ' + TableName + 
        '(' + SUBSTRING(ixcols, 1, LEN(ixcols)-1) + 
        CASE LEN(includedcols)
          WHEN 0 THEN ')'
          ELSE ') INCLUDE (' + SUBSTRING(includedcols, 1, LEN(includedcols)-1) + ')'
        END
FROM 
   indexCTE2
ORDER BY 
   TableName, IndexName

Får du CREATE INDEX uttalanden du letar efter?

Marc