Använda PIVOT Du kan göra följande
With SampleData AS
(
SELECT 'Team1' as Team , 'example@sqldat.com' as email, 'A' as Groups
UNION SELECT 'Team1' as Team , 'example@sqldat.com' as email, 'B' as Groups
UNION SELECT 'Team1' as Team , 'example@sqldat.com' as email, 'C' as Groups
UNION SELECT 'Team2' as Team , 'example@sqldat.com' as email, 'A' as Groups
UNION SELECT 'Team2' as Team , 'example@sqldat.com' as email, 'B' as Groups
UNION SELECT 'Team2' as Team , 'example@sqldat.com' as email, 'C' as Groups
)
SELECT Team, A, B,C FROM
(SELECT * FROM SampleData) source
PIVOT
(MAX(email) FOR Groups IN ([A], [B], [C]) )as pvt
Producerar
Team A B C
----- ---------------- ---------------- ----------------
Team1 example@sqldat.com example@sqldat.com example@sqldat.com
Team2 example@sqldat.com example@sqldat.com example@sqldat.com
Se ett fungerande Data.SE-exempel
I en DB som inte stöder PIVOT kan du istället göra flera kopplingar till din tabell. Även om du kanske vill ändå, eftersom som GBN påpekade, eftersom vi inte använder ett aggregat.
With SampleData AS
(
SELECT 'Team1' as Team , 'example@sqldat.com' as email, 'A' as Groups
UNION SELECT 'Team1' as Team , 'example@sqldat.com' as email, 'B' as Groups
UNION SELECT 'Team1' as Team , 'example@sqldat.com' as email, 'C' as Groups
UNION SELECT 'Team2' as Team , 'example@sqldat.com' as email, 'A' as Groups
UNION SELECT 'Team2' as Team , 'example@sqldat.com' as email, 'B' as Groups
UNION SELECT 'Team2' as Team , 'example@sqldat.com' as email, 'C' as Groups
)
SELECT
source.Team,
A.email,
B.email,
C.email
FROM
(SELECT DISTINCT TEAM From SampleData) source
LEFT JOIN SampleData A
ON source.Team = A.Team
AND A.GROUPS = 'A'
LEFT JOIN SampleData B
ON source.Team = B.Team
AND B.GROUPS = 'B'
LEFT JOIN SampleData C
ON source.Team = C.Team
AND C.GROUPS = 'C'
Se ett fungerande Data.SE-exempel